document.write( "Question 962295: Find the exact value of the expression: \"+sin+%28+pi%2F6+%29+%2B+tan%5E2+%28+pi%2F5+%29.%0D%0A\"
\n" ); document.write( "I am familiar with some of the trigonometric identities, however for some reason this one has me stumped. I attempted to convert them into their reciprocals, cosecant and cotangent in order to try and see if it lined up with the following identity.\r
\n" ); document.write( "\n" ); document.write( "csc^2(x) = cot^2(x) + 1 \r
\n" ); document.write( "\n" ); document.write( "That did not seem to work. I think what's messing me up here is the tangent being squared and the sine is not. Unfortunately, with this expression, I'm unsure of where to start.
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Algebra.Com's Answer #587900 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
I do not think you need to use identities to solve this\r
\n" ); document.write( "\n" ); document.write( "\"+sin+%28+pi%2F6+%29+%2B+tan%5E2+%28+pi%2F5+%29\"\r
\n" ); document.write( "\n" ); document.write( "since \"+sin+%28+pi%2F6+%29=1%2F2\", and\r
\n" ); document.write( "\n" ); document.write( "\"tan%5E2+%28+pi%2F5+%29=tan+%28+pi%2F5+%29%2Atan%28+pi%2F5+%29\", and\r
\n" ); document.write( "\n" ); document.write( "\"tan+%28+pi%2F5+%29=sqrt%285-2+sqrt%285%29%29\" then\r
\n" ); document.write( "\n" ); document.write( "\"tan%5E2+%28+pi%2F5+%29=%28sqrt%285-2sqrt%285%29%29%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"tan%5E2+%28+pi%2F5+%29=5-2sqrt%285%29\"\r
\n" ); document.write( "\n" ); document.write( "so we have:\r
\n" ); document.write( "\n" ); document.write( "\"+1%2F2+%2B+%285-2sqrt%285%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"+1%2F2+%2B+10%2F2-2sqrt%285%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"+11%2F2-2sqrt%285%29%29\"\r
\n" ); document.write( "\n" ); document.write( "the exact value of the expression is:\"11%2F2-2sqrt%285%29\"\r
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