document.write( "Question 82050: 500 milliliters of 20% acid solution needs to be combined with what percent solution to get 800 milliliters of 38 solution? \n" ); document.write( "
Algebra.Com's Answer #58786 by stanbon(75887)\"\" \"About 
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500 milliliters of 20% acid solution needs to be combined with what percent solution to get 800 milliliters of 38% solution?
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\n" ); document.write( "20% solution DATA:
\n" ); document.write( "Amt = 500 ml ; amt of acid is 0.20*500 = 100 ml
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\n" ); document.write( "x% solution DATA:
\n" ); document.write( "Amt. = 300 ml ; amt of acid = (x/100)*300 = 3x ml
\n" ); document.write( "38% solution DATA:
\n" ); document.write( "Amt = 800 ml ; Amt of acid = 0.38*800 = 304 ml\r
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\n" ); document.write( "EQUATION:
\n" ); document.write( "acid + acid = acid
\n" ); document.write( "100 + 3x = 304
\n" ); document.write( "3x = 204
\n" ); document.write( "x = 68% (the 500 ml has to be combined with 300 ml of 68% solution)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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