document.write( "Question 82050: 500 milliliters of 20% acid solution needs to be combined with what percent solution to get 800 milliliters of 38 solution? \n" ); document.write( "
Algebra.Com's Answer #58786 by stanbon(75887) ![]() You can put this solution on YOUR website! 500 milliliters of 20% acid solution needs to be combined with what percent solution to get 800 milliliters of 38% solution? \n" ); document.write( "----------- \n" ); document.write( "20% solution DATA: \n" ); document.write( "Amt = 500 ml ; amt of acid is 0.20*500 = 100 ml \n" ); document.write( "------------ \n" ); document.write( "x% solution DATA: \n" ); document.write( "Amt. = 300 ml ; amt of acid = (x/100)*300 = 3x ml \n" ); document.write( "38% solution DATA: \n" ); document.write( "Amt = 800 ml ; Amt of acid = 0.38*800 = 304 ml\r \n" ); document.write( "\n" ); document.write( "---------------- \n" ); document.write( "EQUATION: \n" ); document.write( "acid + acid = acid \n" ); document.write( "100 + 3x = 304 \n" ); document.write( "3x = 204 \n" ); document.write( "x = 68% (the 500 ml has to be combined with 300 ml of 68% solution) \n" ); document.write( "============ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |