document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=962223>Question 962223</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose sin(t)=-3/4 amd sec(t)<0. Use identities\r<BR>\n" );
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document.write( "cos(-t) why does (t) become positive instead of negative? I don't understand this idea at all.\r<BR>\n" );
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document.write( "Please help\r<BR>\n" );
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document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #587835 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=587835\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Suppose sin(t)=-3/4 amd sec(t)<0. Use identities <BR>\n" );
document.write( "cos(-t) why does (t) become positive instead of negative? I don't understand this idea at all. <BR>\n" );
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document.write( "I'm not sure what your question is, but my guess it is something about the following Identity:<BR>\n" );
document.write( "cosx=cos(-x)<BR>\n" );
document.write( "The cos function is always positive whether the angle is in quadrant I or quadrant IV, or the right half of the unit circle. Its negative in the left half of the unit circle.<BR>\n" );
document.write( "Similarly, the sin function is positive in the top half and negative in the bottom half of the unit circle.<BR>\n" );
document.write( "hope I answered your question. </SPAN>\n" );
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