document.write( "Question 962122: You invested 10,000 in two stocks paying 8% and 10% annual interest. At the end of the year the total interest from these investments was 940. How much was invested at each rate? \n" ); document.write( "

Algebra.Com's Answer #587790 by addingup(3677) $\"\"$ $\"About$

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Of 10,000, a certain amount pays 8%. The rest of the money pays 10%. In other words, x money pays .08, so we can say .08x And what is left of the 10,000 pays .10. So we can say:
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\n" ); document.write( ".08x+.10*10,000-x= 940 Multiply on left:
\n" ); document.write( ".08x+ 1000-x= 940 Subtract 1000 on both sides and do subtraction on left:
\n" ); document.write( "-.02x= -60 Divide both sides by -.02:
\n" ); document.write( "x= -60/-.02
\n" ); document.write( "x= 3000 This is the amount that pays 8% And 10,000-3,000= 7,000 pays 10%.
\n" ); document.write( "Let's see:
\n" ); document.write( "3,000*.08= 240
\n" ); document.write( "7,000*.10= 700
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\n" ); document.write( "Total......940 \n" ); document.write( "

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