document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=961925>Question 961925</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve this by using substitution? y=2x+3 and y=7x-2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #587749 by </B><A HREF=/tutors/aboutme.mpl?userid=EdenWolf><B>EdenWolf(517)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=EdenWolf><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=EdenWolf><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=587749\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We know what y equals, so plug 2x+3 into y in the second equation and solve for x first.\r<BR>\n" );
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document.write( "2x+3=7x-2<BR>\n" );
document.write( "2x+5=7x<BR>\n" );
document.write( "5=5x<BR>\n" );
document.write( "x=1\r<BR>\n" );
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document.write( "So we know what x is, so now we find y. Plug the value of x, or 1, into any of the two equations. (Let's use the first one.)\r<BR>\n" );
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document.write( "y=2*1+3<BR>\n" );
document.write( "y=2+3<BR>\n" );
document.write( "y=5\r<BR>\n" );
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document.write( "So we know that x = 1, and y = 5. </SPAN>\n" );
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