document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=11338>Question 11338</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many pounds of candy selling for $5.80 per pound should be mixed with 7 punds of candy selling for $2.40 per pund to obtain a mixture for $3.42 per pound? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #5877 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=5877\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> this is an easy question to solve, once you get past all the english.\r<BR>\n" );
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document.write( "First let x = amount of candy required (at £5.80).\r<BR>\n" );
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document.write( "so, we have candy1 + candy2 = (mixture)...that is all there is to it!\r<BR>\n" );
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document.write( "so we have 5.80x + 7(2.40) = (7+x)*3.42<BR>\n" );
document.write( "5.80x + 16.80 = 23.94 + 3.42x<BR>\n" );
document.write( "2.38x = 7.14<BR>\n" );
document.write( "x = 3\r<BR>\n" );
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document.write( "so, we need 3lb of the first candy.\r<BR>\n" );
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document.write( "jon.<BR>\n" );
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