document.write( "Question 961876: the perimeter of a triangle is 73cm. the triangle is isosceles now, but if you lengthened the base by 5 cm and shortened each side by 6cm it would be equilateral. find the base of the original triangle. \n" ); document.write( "
Algebra.Com's Answer #587696 by ankor@dixie-net.com(22740)\"\" \"About 
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the perimeter of a triangle is 73cm. the triangle is isosceles now, but if you lengthened the base by 5 cm and shortened each side by 6cm it would be equilateral. find the base of the original triangle.
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\n" ); document.write( "let b = the base of the original triangle
\n" ); document.write( "let s = two equal sides
\n" ); document.write( ":
\n" ); document.write( "\"the perimeter of a triangle is 73cm.\"
\n" ); document.write( "b + 2s = 73
\n" ); document.write( "\" the triangle is isosceles now, but if you lengthened the base by 5 cm and shortened each side by 6cm it would be equilateral.\"
\n" ); document.write( "(sides would be equal)
\n" ); document.write( "(b+5) = (s-6)
\n" ); document.write( "b - s = -6 - 5
\n" ); document.write( "b - s = -11
\n" ); document.write( ":
\n" ); document.write( "Use elimination with these two equations
\n" ); document.write( "b + 2s = 73
\n" ); document.write( "b - s = -11
\n" ); document.write( "-------------Subtraction eliminates b, find s
\n" ); document.write( "0 + 3s = 84
\n" ); document.write( "s = 84/3
\n" ); document.write( "s = 28 cm, the equal side of the original triangle
\n" ); document.write( ":
\n" ); document.write( "\" find the base of the original triangle.\"
\n" ); document.write( "Use b + 2s = 73
\n" ); document.write( "b + 2(28) = 73
\n" ); document.write( "b = 73 - 56
\n" ); document.write( "b = 17 cm the original base
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\n" ); document.write( ":
\n" ); document.write( "Confirm this
\n" ); document.write( "\"lengthened the base by 5 cm and shortened each side by 6cm it would be equilateral. \"
\n" ); document.write( "17 + 5 = 28 - 6
\n" ); document.write( "22 = 22
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