document.write( "Question 82041: Solve the following system by addition. If a unique solution does not exist, state whether the system is inconsistaent or dependent:\r
\n" ); document.write( "\n" ); document.write( "2x+3y=1
\n" ); document.write( "5x+3y=16
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Algebra.Com's Answer #58767 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Linear Systems by Addition
We'll solve the system:
\n" ); document.write( " \"2%2Ax+%2B+3%2Ay+=+1\"
\n" ); document.write( " \"5%2Ax+%2B+3%2Ay+=+16\"
\n" ); document.write( " by elimination by addition.To eliminate by addition, we need to set both coefficients of x to numbers with changed signs, i.e a and -a. Since in the second equation we have 5 as our coefficient for x, to get -2 we have to multiply all terms of the second equation by \"-2%2F5\" which is equal to -0.4.
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\n" ); document.write( " Multiplying, we get on our second equation:\"%285%2A-0.4%29x+%2B+%283%2A-0.4%29y+=+16%2A-0.4\"
\n" ); document.write( " \"-2%2Ax+%2B+-1.2%2Ay+=+-6.4\"
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\n" ); document.write( " Adding both equations we get:
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\n" ); document.write( " \"%282%2B-2%29x+%2B+%283%2B-1.2%29y+=+%281%2B-6.4%29\"
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\n" ); document.write( " Since 2 and -2 cancel out, we have a linear equation:Therefore, we know that y = -3.
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\n" ); document.write( " Plugging that in into the first equation gives us:
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\n" ); document.write( " \"2%2Ax+%2B+3%2Ay+=+1\"
\n" ); document.write( " \"2%2Ax+%2B+3%2A-3+=+1\"
\n" ); document.write( " \"2%2Ax+%2B+-9+=+1\"
\n" ); document.write( " \"2%2Ax+=+1+-+-9\"
\n" ); document.write( " \"x+=+%281+-+-9%29%2F2\"
\n" ); document.write( " \"x+=+10%2F2\"
\n" ); document.write( " \"x+=+5\"
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\n" ); document.write( " Therefore, our answer is:
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\n" ); document.write( " \"system%28+x=5%2C+y=-3+%29\"
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