document.write( "Question 961590: I'm stuck. This problem is not coming out for me. I need help.\r
\n" ); document.write( "\n" ); document.write( "4y=3x-13
\n" ); document.write( "6x+5y=52
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Algebra.Com's Answer #587641 by EdenWolf(517)\"\" \"About 
You can put this solution on YOUR website!
Hello!
\n" ); document.write( "Let's see if I can help you.
\n" ); document.write( "We can solve this system with substitution.
\n" ); document.write( "First pay attention to the first equation.
\n" ); document.write( "\"4y=3x-13\"
\n" ); document.write( "Let's arrange it so it looks like \"y = ...\", so we can plug that value instead of \"y\" in the second equation. So basically divide 4 from both sides to isolate y.
\n" ); document.write( "\"y=%283%2F4%29x-13%2F4\"
\n" ); document.write( "We can turn those fractions into decimals to make it a bit easier to work with. It depends if you work better with fractions or decimals.
\n" ); document.write( "\"y=0.75x-3.25\"
\n" ); document.write( "Now, plug (\"0.75x-3.25\") instead of y in the second equation:
\n" ); document.write( "\"6x%2B5%280.75x-3.25%29=52\"
\n" ); document.write( "So now we are trying to solve for x.
\n" ); document.write( "\"6x%2B3.75x-16.25=52\"
\n" ); document.write( "\"9.75x-16.25=52\"
\n" ); document.write( "\"9.75x=68.25\"
\n" ); document.write( "\"x=7\"
\n" ); document.write( "So we have x now. But wait, we still haven't found y yet. Simply put 7 instead of x in either of the two equations and solve for y. (We'll use the second equation)
\n" ); document.write( "\"6%287%29%2B5y=52\"
\n" ); document.write( "\"42%2B5y=52\"
\n" ); document.write( "\"5y=10\"
\n" ); document.write( "\"y=2\"\r
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\n" ); document.write( "\n" ); document.write( "So there you have it! We now know that x = 7 and y = 2.
\n" ); document.write( "Hope I helped.
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