document.write( "Question 961552: Help me, please? I know the formula is P=Poe^kt, but I don't how to isolate the variable to find Po?!
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document.write( "Consider a particular investment bond that pays out 3% annual interest
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document.write( "compounded continually. If the bond is valued at $10,000 after 10 years,
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document.write( "how much was it worth at 5 years? \n" );
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Algebra.Com's Answer #587547 by josgarithmetic(39626) ![]() You can put this solution on YOUR website! P=pe^(kt), using small p to avoid using subscripts. Big P is for balance of the bond after any time t. The formula rendered is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If p=1, the in 1 year, t=1, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Your description of P=10000 after t=10 means you still want to know the initial investment amount. \n" ); document.write( "- \n" ); document.write( "ln(P)=ln(p)+ln(e^(kt)) \n" ); document.write( "ln(P)=ln(p)+kt*1 \n" ); document.write( "ln(P)-kt=ln(p) \n" ); document.write( "- \n" ); document.write( "those steps seem unnecessary although correct.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "BETTER----------------------------------------- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Just 5 years instead of 10 years? \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |