document.write( "Question 961552: Help me, please? I know the formula is P=Poe^kt, but I don't how to isolate the variable to find Po?!
\n" ); document.write( "Consider a particular investment bond that pays out 3% annual interest
\n" ); document.write( "compounded continually. If the bond is valued at $10,000 after 10 years,
\n" ); document.write( "how much was it worth at 5 years?
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Algebra.Com's Answer #587547 by josgarithmetic(39626)\"\" \"About 
You can put this solution on YOUR website!
P=pe^(kt), using small p to avoid using subscripts. Big P is for balance of the bond after any time t. The formula rendered is \"P=pe%5E%28kt%29\". Your goal is in part, to isolate p, which you can do multiplying both sides by \"e%5E%28-kt%29\". \r
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\n" ); document.write( "\n" ); document.write( "If p=1, the in 1 year, t=1, \"P=1%2Ae%5E%280.03%2A1%29\", \"P=e%5E%280.03%29=1.0304\", reasonably near the expected 3% increase. The value of constant k is the same as the interest rate of 3% or 0.03=r=k.\r
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\n" ); document.write( "\n" ); document.write( "Your description of P=10000 after t=10 means you still want to know the initial investment amount.
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\n" ); document.write( "ln(P)=ln(p)+ln(e^(kt))
\n" ); document.write( "ln(P)=ln(p)+kt*1
\n" ); document.write( "ln(P)-kt=ln(p)
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\n" ); document.write( "those steps seem unnecessary although correct.\r
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\n" ); document.write( "\n" ); document.write( "BETTER-----------------------------------------
\n" ); document.write( "\"pe%5E%28kt%29=P\"
\n" ); document.write( "\"p=P%2Fe%5E%28kt%29\"-----you could use a calculator for this.
\n" ); document.write( "\"p=10000%2F%28e%5E%280.03%2A10%29%29\"
\n" ); document.write( "\"p=10000%2F%28e%5E%280.3%29%29\"
\n" ); document.write( "\"highlight%28p=7408.18%29\", the initial investment amount.\r
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\n" ); document.write( "\n" ); document.write( "Just 5 years instead of 10 years?
\n" ); document.write( "\"P=7408.18%2Ae%5E%280.03%2A5%29\"
\n" ); document.write( "\"P=7408.18%2A1.1618342427\"
\n" ); document.write( "\"highlight%28P=8607.08%29\"
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