document.write( "Question 961500: If r = 7 cm and h = 5 cm, what is the approximate surface area of the cylinder? (Use 3.14 for pi.) \n" ); document.write( "
Algebra.Com's Answer #587522 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( " Well if you can make the cylinder with the rectangle and the two circles, you can use them to derive the surface area of the cylinder.\r
\n" ); document.write( "\n" ); document.write( "The area of the two circles is straightforward. The area of one circle is \"pi+%2Ar%5E2\", so for two circles, you get \"2+%2A+pi+%2A+r%5E2\"\r
\n" ); document.write( "\n" ); document.write( "-the longest side or folded side of the rectangle must be equal to \"2+%2A+pi+%2A+r\", which is the circumference of the circle\r
\n" ); document.write( "\n" ); document.write( "To get the area of the rectangle, multiply \"h\" by \"2%2A+pi+%2A+r\" and that is equal to \"2+%2A+pi+%2A+r+%2Ah\".\r
\n" ); document.write( "\n" ); document.write( "Therefore, the total surface area of the cylinder, call it \"SA\" is:\r
\n" ); document.write( "\n" ); document.write( "\"SA+=+2+%2A+pi+%2A+r%5E2+%2B+++2+%2A+pi+%2A+r+%2Ah\"........plug in given values \"r+=+7cm\" and \"h+=+5cm\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"SA+=+2+%2A+3.14+%2A+%287cm%29%5E2+%2B+++2+%2A+3.14%2A%287cm%29+%2A%285cm%29\"\r
\n" ); document.write( "\n" ); document.write( "\"SA+=+6.28+%2A+49cm%5E2+%2B+++6.28%2A7cm+%2A5cm\"\r
\n" ); document.write( "\n" ); document.write( "\"SA+=+307.72cm%5E2+%2B++219.8cm%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"SA+=+527.52cm%5E2\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );