document.write( "Question 11339: 7) The correct solution to 3=2√x+x is:
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document.write( " a. x=1 and x=3
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document.write( " b. x=1 and x= 4
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document.write( " c. x=1 and x=9
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document.write( "I can not figure this out...this is what I keep getting:
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document.write( "3=2√x+x
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document.write( "9=4x+x²
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document.write( "x²+4x-9=0\r
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document.write( "And my answer does not factor into any of the possible answers, so I am completely stuck. Can you help me? \n" );
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Algebra.Com's Answer #5875 by longjonsilver(2297)![]() ![]() You can put this solution on YOUR website! you have done THE classic error when squaring. You cannot square each term...you square EACH SIDE, so you would have:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The secret is to get the term with the square root in it by itself and THEN square both sides, as follows.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now square both sides, to give \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "(x-9)(x-1) = 0\r \n" ); document.write( "\n" ); document.write( "--> x-9=0 OR x-1=0 \n" ); document.write( "so x=9 or x=1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "jon. \n" ); document.write( " \n" ); document.write( " |