document.write( "Question 961452: I am having a bit of trouble with this question, I've set it up, but I can't seem to get the correct answer.
\n" );
document.write( "A phone company offers two monthly charge plans. In Plan A, the customer pays a monthly fee of $6.60 and then an additional 8 cents per minute of use. In Plan B, there is no monthly fee, but the customer pays 9 cents per minute of use. \n" );
document.write( "
Algebra.Com's Answer #587492 by addingup(3677)![]() ![]() You can put this solution on YOUR website! So, I think your question is incomplete. Are you supposed to 1)find out at what point one service is cheaper than the other, or 2)does the problem ask you \"if you use x minutes, which one is cheaper?\" Since I have no information for 2), I'll give you the answer to 1): at how many minutes does one plan become cheaper than the other. \n" ); document.write( "6.60+.08x = .09x Subtract .08 from both sides: \n" ); document.write( "6.60= .01x Divide both sides by .01 \n" ); document.write( "660= x At 660 minutes of usage, both plans would cost you exactly the same. \n" ); document.write( "A: 6.60+.08(660)= 6.60+52.08= 59.40 \n" ); document.write( "B: .09(660)= 59.40 \n" ); document.write( "From 660 minutes on, the .08 plan is cheaper. Try it, in A: and B: above, substitute 660 with a higher number, any number you like. Maybe just one minute more, like 661: 6.60+.08(661)= 59.48 and .09(661)= 59.49 From here, the more minutes the cheaper plan A will be.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |