document.write( "Question 961264: Explain why 2^x = 15 cannot always be solved in the same way as 2^x = 16. How would you solve each? \n" ); document.write( "
Algebra.Com's Answer #587437 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"2%5Ex+=+15\" since \"15\" cannot be written as exponent with base \"2\", to solve it we need to take log of both sides\r
\n" ); document.write( "\n" ); document.write( "\"log%282%5Ex%29+=+log%2815%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2Alog%282%29+=+log%283%2A5%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2Alog%282%29+=+log%283%29%2Blog%285%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x=+%28log%283%29%2Blog%285%29%29%2Flog%282%29+\"\r
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\n" ); document.write( "\n" ); document.write( "and \r
\n" ); document.write( "\n" ); document.write( "\"2%5Ex+=+16\" since \"16\" cant be written as exponent with base \"2\" as \"2%5E4\", we will have\r
\n" ); document.write( "\n" ); document.write( "\"2%5Ex+=+2%5E4\"...since base same , we have\r
\n" ); document.write( "\n" ); document.write( "\"x=4\" \r
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