document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=961261>Question 961261</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please solve this problem and show me how to do it? Than you.\r<BR>\n" );
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document.write( "How many g of gold should a coin of 53% gold be if when combined with a 5 g pure gold necklace, it forms a metal that is 76% gold?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #587432 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=587432\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How many g of gold should a coin of 53% gold be if when combined with a 5 g pure gold necklace, it forms a metal that is 76% gold?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "gold + gold = gold<BR>\n" );
document.write( "0.53x + 1*5 = 0.76(x+5)<BR>\n" );
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document.write( "Multiply thru by 100 to get::<BR>\n" );
document.write( "53x + 100*5 = 76*x + 76*5<BR>\n" );
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document.write( "23x = 24*5<BR>\n" );
document.write( "x = 5.217 grams (amt of 53% gold to add)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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