document.write( "Question 961234: The perimeter of a right triangle is 60 cm. The length of the hypotenuse is 6 cm more than twice the length of one of the other sides. Find the length of all three sides. \n" ); document.write( "
Algebra.Com's Answer #587420 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
The perimeter of a right triangle is 60 cm. The length of the hypotenuse is 6 cm more than twice the length of one of the other sides. Find the length of all three sides.
\n" ); document.write( "***
\n" ); document.write( "let x=one of the sides
\n" ); document.write( "2x+6=hypotenuse
\n" ); document.write( "other side=√((2x+6)^2-x^2)=√(4x^2+24x+36-x^2)=√(3x^2+24x+36)
\n" ); document.write( "..
\n" ); document.write( "x+(2x+6)+√(3x^2+24x+36)=60
\n" ); document.write( "√(3x^2+24x+36)=54-3x
\n" ); document.write( "square both sides
\n" ); document.write( "3x^2+24x+36=2916-324x+9x2
\n" ); document.write( "6x^2-348x+2880=0
\n" ); document.write( "x^2-58x+480=0
\n" ); document.write( "(x-10)(x-48)=0
\n" ); document.write( "x=48(reject, extraneous root)
\n" ); document.write( "x=10
\n" ); document.write( "2x+6=26
\n" ); document.write( "√(3x^2+24x+36)=√(300+240+36)=√576=24
\n" ); document.write( "..
\n" ); document.write( "one of the sides=10
\n" ); document.write( "hypotenuse=26
\n" ); document.write( "other side=24\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );