document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=961030>Question 961030</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello,<BR>\n" );
document.write( "Can you please help me solve this problem:<BR>\n" );
document.write( "Give the exact value :<BR>\n" );
document.write( "cos(sin^-1(2/3)+tan^-1(5/6))\r<BR>\n" );
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document.write( "Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #587373 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=587373\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> cos(sin^-1(2/3) + tan^-1(5/6)) <BR>\n" );
document.write( "we use the inverse trig function<BR>\n" );
document.write( "sin^-1(2/3) = 41.810314896<BR>\n" );
document.write( "tan^-1(5/6) = 39.805571092<BR>\n" );
document.write( "need to calculate<BR>\n" );
document.write( "cos (41.810314896 + 39.805571092) = 0.145808735<BR>\n" );
document.write( " </SPAN>\n" );
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