document.write( "Question 961041: Starting at home, Christopher traveled uphill to the grocery store for 90 minutes at just 4 mph. He then traveled back home along the same path downhill at a speed of 12 mph.\r
\n" );
document.write( "\n" );
document.write( "What is his average speed for the entire trip from home to the grocery store and back? \n" );
document.write( "
Algebra.Com's Answer #587351 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Starting at home, Christopher traveled uphill to the grocery store for 90 minutes at just 4 mph. He then traveled back home along the same path downhill at a speed of 12 mph. \n" ); document.write( "What is his average speed for the entire trip from home to the grocery store and back? \n" ); document.write( "*** \n" ); document.write( "90 min=90/60=1.5 hr \n" ); document.write( "distance from home to the grocery store=travel time*speed=(1.5)*4=6 mi \n" ); document.write( "travel time from grocery store to home=distance/speed=6/12=1/2 hr \n" ); document.write( "average speed=total distance/total travel time=12/2=6 mph \n" ); document.write( " |