document.write( "Question 960974: Find the vertices and foci of the hyperbola.
\n" ); document.write( "9x2 − y2 − 36x − 2y + 26 = 0 \n" ); document.write( "
Algebra.Com's Answer #587322 by lwsshak3(11628)\"\" \"About 
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Find the vertices and foci of the hyperbola.
\n" ); document.write( "9x2 − y2 − 36x − 2y + 26 = 0
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\n" ); document.write( "Rewrite:
\n" ); document.write( "9x^2-36x-y^2-2y=-26
\n" ); document.write( "complete the square:
\n" ); document.write( "9(x^2-4x+4)-(y^2+2y+1)=-26+36-1
\n" ); document.write( "9(x-2)^2-(y+1)^2=9
\n" ); document.write( "\"%28x-2%29%5E2-%28y%2B1%29%5E2%2F9=1\"
\n" ); document.write( "hyperbola has a horizontal transverse axis.
\n" ); document.write( "Its standard form of equation: \"%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1\", (h,k)=coordinates of center
\n" ); document.write( "center: (2, -1)
\n" ); document.write( "a^2=1
\n" ); document.write( "a=1
\n" ); document.write( "b^2=9
\n" ); document.write( "b=3
\n" ); document.write( "vertices: (2±a,-1)=(2±1,-1)=(1, -1) and (3,-1)
\n" ); document.write( "c^2=a^2+b^2=1-9=10
\n" ); document.write( "c=√10≈3.16
\n" ); document.write( "foci: (2±c,-1)=(2±3.16,-1)=(1.16, -1) and (5.16,-1) \n" ); document.write( "
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