document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=960997>Question 960997</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with these questions:\r<BR>\n" );
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document.write( "A certain amount of Californium-251 is slowly decaying. After 101 years 92.5 grams of an initial 100 grams are remaining.\r<BR>\n" );
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document.write( "a. Create a function, Q(t), that will calculate how much Californium-251 is remaining after t years.\r<BR>\n" );
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document.write( "b. What is the approximate half-life of Californium-251?\r<BR>\n" );
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document.write( "This is what I did for part a:\r<BR>\n" );
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document.write( "92.5 - 100(x)^101<BR>\n" );
document.write( ".925 = x^101<BR>\n" );
document.write( "I got stuck after that. I don't know how to solve for 'x'\r<BR>\n" );
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document.write( "This is what I did for part b:\r<BR>\n" );
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document.write( "Q(t) = 100(1/2)t/101<BR>\n" );
document.write( "t = 101 - is this correct????<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #587318 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=587318\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A certain amount of Californium-251 is slowly decaying.<BR>\n" );
document.write( " After 101 years 92.5 grams of an initial 100 grams are remaining.<BR>\n" );
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document.write( "a. Create a function, Q(t), that will calculate how much Californium-251 is remaining after t years.<BR>\n" );
document.write( "Q(t) = 100*2^(-t/h), where h = the half-life of the substance<BR>\n" );
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document.write( "b. What is the approximate half-life of Californium-251? <BR>\n" );
document.write( "Q(t) = 92.5 yrs<BR>\n" );
document.write( "100*2^(-101/h) = 92.5<BR>\n" );
document.write( "2^(-101/h) = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=92.5%2F100 ALIGN=MIDDLE  ALT=\"92.5%2F100\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "2^(-101/h) = .925<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-101%2Fh ALIGN=MIDDLE  ALT=\"-101%2Fh\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ln%28.925%29%2Fln%282%29 ALIGN=MIDDLE  ALT=\"ln%28.925%29%2Fln%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "use your calc<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-101%2Fh ALIGN=MIDDLE  ALT=\"-101%2Fh\"   DISABLED_style= \"max-width:90%; height:auto;\" > = -.11247473<BR>\n" );
document.write( "-101 = -.11247473h<BR>\n" );
document.write( "h = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-101%29%2F%28-.11247473%29 ALIGN=MIDDLE  ALT=\"%28-101%29%2F%28-.11247473%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "h = 898 yrs is the half-life<BR>\n" );
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