document.write( "Question 960998: Here is the problem:\r
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document.write( "A certain item costs $4.75. Due to inflation, experts estimate the cost will increase by 2% per year. Approximately how many years until the item costs $7.20?\r
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document.write( "Do I use the growth formula to solve???\r
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document.write( "Q(t) = C * (1+r/t)^t\r
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document.write( "Solve for t to get the answer??? \n" );
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Algebra.Com's Answer #587309 by harpazo(655) You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( "As it is not compounded in a year, the general formula will be FV = PV * (1 + r)^t\r \n" ); document.write( "\n" ); document.write( "FV will be the future value where PV is the present value. r is the the rate (per year) and t shows the years.\r \n" ); document.write( "\n" ); document.write( "7.20 = 4.75 * (1 + 0.02)^t\r \n" ); document.write( "\n" ); document.write( "(1.02)^t = 7.2/4.75\r \n" ); document.write( "\n" ); document.write( "ln (1.02)^t = ln (7.2/4.75)\r \n" ); document.write( "\n" ); document.write( "t = ln (7.2/4.75) / ln (1.02) \n" ); document.write( " \n" ); document.write( "t ≈ 21.004\r \n" ); document.write( "\n" ); document.write( "=> after 21 years \r \n" ); document.write( "\n" ); document.write( "Check this page please \n" ); document.write( "http://www.calculatorsoup.com/calculators/financial/future-value-investment-calculator.php\r \n" ); document.write( "\n" ); document.write( "If we enter the values P = 4.75, R = 2 and t = 21, the result will be 21 years. (m is 1 as the rate isn't compounded) \n" ); document.write( " |