document.write( "Question 953410: the sum of three numbers is 68. the largest is 6 less than twice the smallest, and the middle number is 10 less than the largest. find the three numbers. \r
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Algebra.Com's Answer #587283 by EdenWolf(517)\"\" \"About 
You can put this solution on YOUR website!
Let x = the smallest number, 2x-6 = the largest number, and (2x-6)-10 = the middle number. Set up an equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B2x-6%2B2x-6-10=68\"\r
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\n" ); document.write( "\n" ); document.write( "Now solve for x.\r
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\n" ); document.write( "\n" ); document.write( "\"3x-6%2B2x-6-10=68\"
\n" ); document.write( "\"5x-6-6-10=68\"
\n" ); document.write( "\"5x-12-10=68\"
\n" ); document.write( "\"5x-22=68\"
\n" ); document.write( "\"5x=90\"
\n" ); document.write( "\"x=18\"\r
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\n" ); document.write( "\n" ); document.write( "So we have the smallest number. Now let's plug those in the other two expressions to find the other two numbers.\r
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\n" ); document.write( "\n" ); document.write( "\"2x-6\"
\n" ); document.write( "\"2%2A18-6\"
\n" ); document.write( "\"36-6\"
\n" ); document.write( "\"30\"
\n" ); document.write( "~~~~~~~~
\n" ); document.write( "\"2x-6-10\"
\n" ); document.write( "\"2%2A18-6-10\"
\n" ); document.write( "\"36-6-10\"
\n" ); document.write( "\"30-10\"
\n" ); document.write( "\"20\"\r
\n" ); document.write( "\n" ); document.write( "So the smallest number is 18, the middle number is 20, and the largest number is 30.\r
\n" ); document.write( "\n" ); document.write( "Hope I helped!
\n" ); document.write( "~Eden
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