document.write( "Question 960927: the length of a rectangular field is 50 feet more than the width. if the perimeter of the basketball court is 300 feet, what is the length of the field. \n" ); document.write( "
Algebra.Com's Answer #587255 by addingup(3677)![]() ![]() You can put this solution on YOUR website! The perimeter is the distance around the rectangular field, so you have two lengths and two widths: \n" ); document.write( "2L+2W= P In this problem: \n" ); document.write( "2L+2W= 300 \n" ); document.write( "The problem also says the length equals W+50, so now we have: \n" ); document.write( "2(W+50)+2W= 300 Multiply on the left to get rid of the parenthesis \n" ); document.write( "2W+100+2W= 300 Now add W's on left and subtract 100 on both sides: \n" ); document.write( "4W= 200 Divide both sides by 4 \n" ); document.write( "W= 50 The width is 50 and the length 50+50=100 \n" ); document.write( "Check P(300)= 2L+2W; P(300)= 2(100)+2(50); P(300)= 200+100 We have the correct answer. \n" ); document.write( " \n" ); document.write( " |