document.write( "Question 960913: Coffee costing $4.80 per pound is blended with coffee costing $3.60 per
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document.write( "pound. How many pounds of each must be mixed to obtain 25
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document.write( "pounds of a blend that costs an average of $4.25 per pound? \n" );
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Algebra.Com's Answer #587247 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Coffee costing $4.80 per pound is blended with coffee costing $3.60 per \n" ); document.write( " pound. How many pounds of each must be mixed to obtain 25 \n" ); document.write( " pounds of a blend that costs an average of $4.25 per pound? \n" ); document.write( "------------------ \n" ); document.write( "Equations:: \n" ); document.write( "Quantity:: f + t = 25 lbs \n" ); document.write( "Value::: 4.8f+3.6t = 4.25*25 \n" ); document.write( "------ \n" ); document.write( "Modify for elimination:: \n" ); document.write( "4.8f + 4.8t = 4.8^25 \n" ); document.write( "4.8f + 3.6t = 4.25*25 \n" ); document.write( "----------------------------- \n" ); document.write( "Subtract and solve for \"t\": \n" ); document.write( "1.2t = 0.55*25 \n" ); document.write( "t = 11.46 lbs (amt. of $3.60 coffee needed) \n" ); document.write( "--- \n" ); document.write( "f = 25-11.46 = 13.54 lbs (amt. of $4.80 coffee needed) \n" ); document.write( "-------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "--------------- \n" ); document.write( " \n" ); document.write( " |