document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=960872>Question 960872</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you verify sinxcosx(tanx+cotx)=1?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #587236 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=587236\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you use the distributive law of multiplication plus the fact that sin^2x + cos^x = 1.\r<BR>\n" );
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document.write( "sinxcosx(tanx+cotx) = sinxcosxtanx + sinxcosxcotx = sinxcosxsinx/cosx + sinxcosxcosx/sinx = sin^x + cos^x = 1\r<BR>\n" );
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