document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=960855>Question 960855</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given two numbers such that the difference of the first and the second numbers is 11. If the sum of twice the first number and the second number is 12, find the numbers.<BR>\n" );
document.write( "solution. : <BR>\n" );
document.write( "x - y=11 , where x= 1st no. , y= 2nd no<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #587226 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=587226\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "x=first number; y=second number<BR>\n" );
document.write( "x-y=11<BR>\n" );
document.write( "x=11+y<BR>\n" );
document.write( "2x+y=12 Substitute for x<BR>\n" );
document.write( "2(11+y)+y=12<BR>\n" );
document.write( "22+2y+y=12 Subtract 22 from each side.<BR>\n" );
document.write( "3y=-10 Divide each side by 3<BR>\n" );
document.write( "y=-10/3 ANSWER 1: The second number is -10/3.<BR>\n" );
document.write( "x=11+y=11-10/3=23/3 ANSWER 2: The first number is 23/3.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "23/3-(-10/3)=11<BR>\n" );
document.write( "33/3=11<BR>\n" );
document.write( "11=11<BR>\n" );
document.write( "2x+y=12<BR>\n" );
document.write( "2(23/3)+(-10/3)=12<BR>\n" );
document.write( "46/3-10/3=12<BR>\n" );
document.write( "36/3=12<BR>\n" );
document.write( "12=12 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );