document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=960753>Question 960753</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If cos A = 1/2 with A in QIV, find sec A/2. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #587188 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=587188\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If cos A = 1/2 with A in QIV, find sec A/2.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=cos%28A%2F2%29=-sqrt%28%281%2BcosA%29%2F2%29=-sqrt%28%281%2B%281%2F2%29%29%2F2%29=-sqrt%283%2F4%29=-sqrt%283%29%2F2 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "sec A/2=(1/cosA/2)=-2/&#8730;3=-(2&#8730;3)/3 </SPAN>\n" );
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