document.write( "Question 960704: Express as a single logarithm: (log base a m - log base a n)+ 2log base a k? \n" ); document.write( "
Algebra.Com's Answer #587151 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
your problem is:\r
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\n" ); document.write( "\n" ); document.write( "loga(m) - loga(n) + 2*loga(k)\r
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\n" ); document.write( "\n" ); document.write( "since 2*loga(k) is equal to loga(k^2), then your problem can be restated as:\r
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\n" ); document.write( "\n" ); document.write( "loga(m) - loga(n) + loga(k^2)\r
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\n" ); document.write( "\n" ); document.write( "since loga(m) - loga(n) is equal to loga(m/n), then your problem can be restated as:\r
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\n" ); document.write( "\n" ); document.write( "loga(m/n) + loga(k^2)\r
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\n" ); document.write( "\n" ); document.write( "since loga(m/n) + loga(k^2) is equal to loga(m/n * k^2), then your problem can be restated as:\r
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\n" ); document.write( "\n" ); document.write( "loga(m/n * k^2)\r
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