document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=81931>Question 81931</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395977258/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Identify the CONIC(circle,ellipse,hyperbola) and state the center\r<BR>\n" );
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document.write( "25x^2-4y^2-50x-16y-59=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #58713 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=58713\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> rearranging and separating terms gives 25x^2-50x=4y^2+16y+59 \r<BR>\n" );
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document.write( "completing the squares and factoring gives 25(x-1)^2=4(y+2)^2+43+25 rearranging again gives 25(x-1)^2-4(y+2)^2=68\r<BR>\n" );
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document.write( "the general form of a hyperbola is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28%28%28x-h%29%5E2%29%2Fa%29-%28%28%28y-k%29%5E2%29%2Fb%29=1 ALIGN=MIDDLE  ALT=\"%28%28%28x-h%29%5E2%29%2Fa%29-%28%28%28y-k%29%5E2%29%2Fb%29=1\"   DISABLED_style= \"max-width:90%; height:auto;\" > where (h,k) is the center\r<BR>\n" );
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document.write( "the center of this hyperbola is (1,-2) </SPAN>\n" );
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