document.write( "Question 960750: A Wendy’s fast-food restaurant sells hamburgers and chicken sandwiches. On a typical weekday, the demand for hamburgers is normally distributed with a mean of 450 and standard deviation of 80 and the demand for chicken sandwiches is normally distributed with a mean of 120 and standard deviation of 30. \r
\n" ); document.write( "\n" ); document.write( "How many hamburgers must the restaurant stock to be 99% sure of not running out on a given day?
\n" ); document.write( "

Algebra.Com's Answer #587126 by mathmate(429)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Given:
\n" ); document.write( "Hamburgers sold daily are normally distributed and have a mean of 450 and standard deviation of 80, i.e. N(450,80).
\n" ); document.write( "
\n" ); document.write( "Require:
\n" ); document.write( "Daily stock of hamburgers necessary in order not to run out 99 times out of 100.
\n" ); document.write( "
\n" ); document.write( "Let X=number required, then we need
\n" ); document.write( "P(x>X)=0.99 which means
\n" ); document.write( "P(Z>(X-450)/80)>0.99
\n" ); document.write( "From normal distribution tables, Z=2.327,
\n" ); document.write( "solve for X
\n" ); document.write( "2.3263=(X-450)/80
\n" ); document.write( "X-450=80*2.3263=186.1
\n" ); document.write( "X=450+186.2=636.1
\n" ); document.write( "
\n" ); document.write( "Answer:
\n" ); document.write( "637 hamburgers should be stocked.
\n" ); document.write( "
\n" );