document.write( "Question 960716: How do I plot ? Why doesn't the y-intercept 0,0 work in this case? \n" );
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Algebra.Com's Answer #587115 by josgarithmetic(39623)![]() ![]() ![]() You can put this solution on YOUR website! f is undefined at x=0, because denominators must not become zero.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You could make x y table of values, but you could also condense the function expression and evaluate a few things about it.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "First notice that as x goes unbounded to the left or the right, f(x) will approach 4x, so this will be a slant asymptote, of y=4x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Where is the numerator 0? \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The three critical x values form intervals: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Evaluate the sign of f in each interval. That will help to determine if f is above or below the horizontal axis.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A vertical asymptote in addition to the slant asymptote, is x=0. \n" ); document.write( " |