document.write( "Question 81911: The length of a rectangle is 2 ft longer than the width. If the area is 16ft^2, then what are the length and width? \n" ); document.write( "

Algebra.Com's Answer #58708 by checkley75(3666) $\"\"$ $\"About$

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L=W+2
\n" ); document.write( "AREA=L*W
\n" ); document.write( "16=(W+2)W
\n" ); document.write( "16=W^2+2W
\n" ); document.write( "W^2+2W-16=0
\n" ); document.write( "USING THE QUADRATIC EQUATION $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$
\n" ); document.write( "WE GET:
\n" ); document.write( "W=(-2+-SQRT[2^2-4*1*-16])/2*1
\n" ); document.write( "W=(-2+-SQRT[4+64])/2
\n" ); document.write( "W=(-2+-SQRT68)/2
\n" ); document.write( "W=(-2+-8.246)/2
\n" ); document.write( "W=(-2+8.246)/2
\n" ); document.write( "W=6.246/2
\n" ); document.write( "W=3.123 ANSWER FOR THE WIDTH.
\n" ); document.write( "L=3.123+2
\n" ); document.write( "L=5.123 ANSWER FOR THE LENGTH.
\n" ); document.write( "PROOF
\n" ); document.write( "3.123*5.123=16
\n" ); document.write( "16=16
\n" ); document.write( " \n" ); document.write( "

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