document.write( "Question 960620: Write the series in expanded form and find the sum. \r
\n" ); document.write( "\n" ); document.write( "5
\n" ); document.write( "∑(4j-16)
\n" ); document.write( "j=1 \r
\n" ); document.write( "\n" ); document.write( "A. (4 ∙ 1 - 16) - (4 ∙ 2 - 16) - (4 ∙ 3 - 16) - (4 ∙ 4 - 16) - (4 ∙ 5 - 16) = -20\r
\n" ); document.write( "\n" ); document.write( "B. (4 ∙ 1 - 16) + (4 ∙ 2 - 16) + (4 ∙ 3 - 16) + (4 ∙ 4 - 16) + (4 ∙ 5 - 16) = -20\r
\n" ); document.write( "\n" ); document.write( "C. (4 ∙ 1 16) + (4 ∙ 5 - 16) = -8\r
\n" ); document.write( "\n" ); document.write( "D. (4 ∙ 1 - 16) - (4 ∙ 5 - 16) = -16 \n" ); document.write( "

Algebra.Com's Answer #587060 by Edwin McCravy(20056) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "That means to substitute 1, 2, 3, 4, and 5 for j in (4j-16)\r\n" );
document.write( "and add all these 5 values, so when you do that you get (b).\r\n" );
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document.write( "Edwin

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