document.write( "Question 960538: How do you find the current of a river when the paddle boat takes 57 min to travel 4 miles up and back at a speed10miles per hour? \n" ); document.write( "
Algebra.Com's Answer #587054 by ankor@dixie-net.com(22740)\"\" \"About 
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How do you find the current of a river when the paddle boat takes 57 min to travel 4 miles up and back at a speed 10miles per hour?
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\n" ); document.write( "Let c = the rate of the current
\n" ); document.write( "then
\n" ); document.write( "(10-c) = effective speed up-river
\n" ); document.write( "and
\n" ); document.write( "(10+c) = effective speed down-river
\n" ); document.write( ":
\n" ); document.write( "Convert 57 min to hrs; 57/60
\n" ); document.write( ":
\n" ); document.write( "Write a time equation, time = dist/speed
\n" ); document.write( "\"4%2F%28%2810-c%29%29\" + \"4%2F%28%2810%2Bc%29%29\" = \"57%2F60\"
\n" ); document.write( "multiply 60(10+c)(10-c)
\n" ); document.write( "60(10+c)(10-c)*\"4%2F%28%2810-c%29%29\" + 60(10+c)(10-c)*\"4%2F%28%2810%2Bc%29%29\" = 60(10+c)(10-c)\"57%2F60\"
\n" ); document.write( "cancel the denominators
\n" ); document.write( "60(10+c)*4 + 60(10-c)*4 = 57(10+c)(10-c)
\n" ); document.write( "2400 + 240c + 2400 - 240c = 57(100-c^2)
\n" ); document.write( "4800 = 5700 - 57c^2
\n" ); document.write( "57c^2 = 5700 - 4800
\n" ); document.write( "57c^2 = 900
\n" ); document.write( "c^2 = \"900%2F57\"
\n" ); document.write( "c = \"sqrt%2815.789%29\"
\n" ); document.write( "c = 3.97 ~ 4 mph is the current
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\n" ); document.write( "Check this, find the actual time each way
\n" ); document.write( "4/6 = .667 hrs
\n" ); document.write( "4/14 = .285 hrs
\n" ); document.write( "----------------
\n" ); document.write( "total: .952 hrs which is .952(60) = 57 min
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