document.write( "Question 960538: How do you find the current of a river when the paddle boat takes 57 min to travel 4 miles up and back at a speed10miles per hour? \n" ); document.write( "
Algebra.Com's Answer #587054 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! How do you find the current of a river when the paddle boat takes 57 min to travel 4 miles up and back at a speed 10miles per hour? \n" ); document.write( ": \n" ); document.write( "Let c = the rate of the current \n" ); document.write( "then \n" ); document.write( "(10-c) = effective speed up-river \n" ); document.write( "and \n" ); document.write( "(10+c) = effective speed down-river \n" ); document.write( ": \n" ); document.write( "Convert 57 min to hrs; 57/60 \n" ); document.write( ": \n" ); document.write( "Write a time equation, time = dist/speed \n" ); document.write( " \n" ); document.write( "multiply 60(10+c)(10-c) \n" ); document.write( "60(10+c)(10-c)* \n" ); document.write( "cancel the denominators \n" ); document.write( "60(10+c)*4 + 60(10-c)*4 = 57(10+c)(10-c) \n" ); document.write( "2400 + 240c + 2400 - 240c = 57(100-c^2) \n" ); document.write( "4800 = 5700 - 57c^2 \n" ); document.write( "57c^2 = 5700 - 4800 \n" ); document.write( "57c^2 = 900 \n" ); document.write( "c^2 = \n" ); document.write( "c = \n" ); document.write( "c = 3.97 ~ 4 mph is the current \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this, find the actual time each way \n" ); document.write( "4/6 = .667 hrs \n" ); document.write( "4/14 = .285 hrs \n" ); document.write( "---------------- \n" ); document.write( "total: .952 hrs which is .952(60) = 57 min \n" ); document.write( " \n" ); document.write( " |