document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=960574>Question 960574</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A firm has tendered for two independent contracts. It estimates that it has probability 0.4 of obtaining contract A and probability 0.1 of obtaining contract B. Find the probability that the firm: (i) obtains both contracts. (ii) obtains neither of the contracts (iii) obtains exactly one contract. Pls solve it for me now </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #587043 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=587043\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Probility(Pr)<BR>\n" );
document.write( "i) Pr (both contracts occur) = (4/10) * (1/10) = 4/100 = .04<BR>\n" );
document.write( "ii) Pr(neither contract occurs) = (6/10) * (9/10) = 54/100 = .54<BR>\n" );
document.write( "note if Pr of getting contract is .4, then not getting contract is 1 - .4 = .6<BR>\n" );
document.write( "iii) Pr (at least one contract occurs) = .4 + .1 = .5\r<BR>\n" );
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