document.write( "Question 81878: I have tried this problem for rational equations and I am unable to get the \"work shown\" correct. Please help. Thank you\r
\n" ); document.write( "\n" ); document.write( "Original problem: (N - 1) / (N^2 - 4) = 6 / (N + 2)
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\n" ); document.write( "(n - 1) / (n^2 - 4) = 6 / (n + 2)
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\n" ); document.write( "denomin: (n^2 - 4), (n + 2)
\n" ); document.write( "(n + 2)(n - 2) LCD: (n + 2)(n - 2)
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\n" ); document.write( "I again need some guidence from here on, I think I get mixed up sometimes with the examples.
\n" ); document.write( "multiply each of the two \"fractions\" by (n+2)(n-2) / (n+2)(n-2) cancelling all that you can first.
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\n" ); document.write( "CORRECTION:
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\n" ); document.write( "when I multiply (n+2)(n-2) / (n+2)(n-2), I come up with, 0 (zero),
\n" ); document.write( "(n + 2) (n - 2) * (n - 2)(n + 2) cancelling cancels all. I do not think this is correct.
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Algebra.Com's Answer #58704 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
you're right about the LCD, multiplying the right hand side by (n-2)/(n-2) will produce the same denominator on both sides\r
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\n" ); document.write( "\n" ); document.write( "multiplying the equation (by LCD) to clear the denominator leaves (n-1)=6(n-2)\r
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\n" ); document.write( "\n" ); document.write( "so n-1=6n-12 ... 11=5n ... n=11/5
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