document.write( "Question 960543: Stella drove her car 45 mi. She ran out of gas and had to walk 3 mi to a gas station. Her speed driving is 15 times her speed walking.If the total time for driving and walking is 1 1/2 hour, what was her speed driving? \n" ); document.write( "
Algebra.Com's Answer #587029 by lwsshak3(11628)\"\" \"About 
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Stella drove her car 45 mi. She ran out of gas and had to walk 3 mi to a gas station. Her speed driving is 15 times her speed walking.If the total time for driving and walking is 1 1/2 hour, what was her speed driving?
\n" ); document.write( "***
\n" ); document.write( "let x=Stella's walking speed
\n" ); document.write( "15x=Stella's driving speed
\n" ); document.write( "..
\n" ); document.write( "\"45%2F15x%2B3%2Fx=3%2F2\"
\n" ); document.write( "lcd:15x
\n" ); document.write( "45+45=45x/2
\n" ); document.write( "45x=180
\n" ); document.write( "x=4
\n" ); document.write( "15x=60
\n" ); document.write( "Stella's walking speed=4 mph
\n" ); document.write( "Stella's driving speed=60 mph
\n" ); document.write( "
\n" );