document.write( "Question 960543: Stella drove her car 45 mi. She ran out of gas and had to walk 3 mi to a gas station. Her speed driving is 15 times her speed walking.If the total time for driving and walking is 1 1/2 hour, what was her speed driving? \n" ); document.write( "
Algebra.Com's Answer #587029 by lwsshak3(11628) ![]() You can put this solution on YOUR website! Stella drove her car 45 mi. She ran out of gas and had to walk 3 mi to a gas station. Her speed driving is 15 times her speed walking.If the total time for driving and walking is 1 1/2 hour, what was her speed driving? \n" ); document.write( "*** \n" ); document.write( "let x=Stella's walking speed \n" ); document.write( "15x=Stella's driving speed \n" ); document.write( ".. \n" ); document.write( " \n" ); document.write( "lcd:15x \n" ); document.write( "45+45=45x/2 \n" ); document.write( "45x=180 \n" ); document.write( "x=4 \n" ); document.write( "15x=60 \n" ); document.write( "Stella's walking speed=4 mph \n" ); document.write( "Stella's driving speed=60 mph \n" ); document.write( " |