document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=960541>Question 960541</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the diameter of a sphere with volume 576pi in^3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #587026 by </B><A HREF=/tutors/aboutme.mpl?userid=simranb><B>simranb(63)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=simranb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=simranb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=587026\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> All you have to do find the volume of the sphere is<BR>\n" );
document.write( "Equate the equation for volume with the value provided in the question<BR>\n" );
document.write( "4/3&#960;*r^3 = 576&#960; (what is in^3, it is not clear)<BR>\n" );
document.write( "But don't worry whatever it is, cancel the pi on both sides and then solve for r by isolating it on the left hand side and taking cube root on right hand side<BR>\n" );
document.write( "Once you have done that, just multiply the result by 2<BR>\n" );
document.write( "As diameter= 2* radius.\r<BR>\n" );
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document.write( "Hope that helps!!!<BR>\n" );
document.write( "Please resend the question with correct value if this doesn't help.<BR>\n" );
document.write( "Cheers!!<BR>\n" );
document.write( "Simran Bhuria </SPAN>\n" );
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