document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=960511>Question 960511</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I do not understand how to find the standard equation of a line through the given point A (2,1) that satisfies the given condition(perpendicular to the y-axis) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #587010 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=587010\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Standard form as a generalized model can be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ax%2Bby=c ALIGN=MIDDLE  ALT=\"ax%2Bby=c\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "If you solve for y in terms of x, you find slope is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-a%2Fb ALIGN=MIDDLE  ALT=\"-a%2Fb\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  \"Perpendicular to the y axis\", means slope is 0.  Using the formula taken from standard form, this means <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-a%2Fb=0 ALIGN=MIDDLE  ALT=\"-a%2Fb=0\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  This means, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28a=0%29 ALIGN=MIDDLE  ALT=\"highlight_green%28a=0%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "You have so far,  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=by=c ALIGN=MIDDLE  ALT=\"by=c\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "You want the line to contain the point A (2,1).  The coordinate of x is no longer important;  all possible values of x will be on the horizontal line (given now that slope is 0).  y is 1 everywhere on this line.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%2A1=c ALIGN=MIDDLE  ALT=\"b%2A1=c\"   DISABLED_style= \"max-width:90%; height:auto;\" >, but also <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=c%2Fb ALIGN=MIDDLE  ALT=\"y=c%2Fb\"   DISABLED_style= \"max-width:90%; height:auto;\" > to give the slope-intercept form of the equation.  Obviously this is only a constant, and therefore  c/b is the y-intercept.  You know that the line is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28y=1%29 ALIGN=MIDDLE  ALT=\"highlight%28y=1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "If you really want as \"STANDARD FORM\", then adjustment is not needed.  b=1, and c=1.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%280%2Ax%2B1%2Ay=1%29 ALIGN=MIDDLE  ALT=\"highlight%280%2Ax%2B1%2Ay=1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, but this is more formal than necessary. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );