document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=960373>Question 960373</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 1cm greater than twice its width. The area of the rectangle is 120cm^2.<BR>\n" );
document.write( "Find the length and width. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #586981 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=586981\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 1cm greater than twice its width. The area of the rectangle is 120cm^2.<BR>\n" );
document.write( "Find the length and width.<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "Area = L*W = 120<BR>\n" );
document.write( "L = 2W + 1<BR>\n" );
document.write( "W*(2W + 1) = 120<BR>\n" );
document.write( "2W^2 + W -120 = 0<BR>\n" );
document.write( "(2W - 15)*(W + 8) = 0<BR>\n" );
document.write( "W = 7.5<BR>\n" );
document.write( "L = 16 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );