document.write( "Question 960361: if sin B=-1/5 with B in Quadrant 3, find cos B/2 \n" ); document.write( "
Algebra.Com's Answer #586901 by Edwin McCravy(20060)\"\" \"About 
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document.write( "Draw angle B in 3rd quadrant:\r\n" );
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document.write( "Since sine = \"y=r\", we make y=-1 and r=5, so that the sin(B)\r\n" );
document.write( "will be \"y%2Fr\"\"%22%22=%22%22\"\"%28-1%29%2F5\".\r\n" );
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document.write( "But we want cos(B) which is \"x%2Fr\"\r\n" );
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document.write( "Then we find x by the Pythagorean relation: \r\n" );
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document.write( "\"x%5E2%2By%5E2=r%5E2\"\r\n" );
document.write( "\"x%5E2%2B%28-1%29%5E2=%285%29%5E2\"\r\n" );
document.write( "\"x%5E2%2B1=25\"\r\n" );
document.write( "\"x%5E2=24\"\r\n" );
document.write( "\"x=+%22%22+%2B-+sqrt%2824%29\"\r\n" );
document.write( "\"x=+%22%22+%2B-+sqrt%284%2A6%29\"\r\n" );
document.write( "\"x+=+%22%22+%2B-+2sqrt%286%29\"\r\n" );
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document.write( "Since x goes to the left, we know to take the negative\r\n" );
document.write( "value \"x+=+-2sqrt%286%29\"\r\n" );
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document.write( "So \"cos%28B%29\"\"%22%22=%22%22\"\"x%2Fr\"\"%22%22=%22%22\"\"%28-2sqrt%286%29%29%2F5\"\"%22%22=%22%22\"\"-2sqrt%286%29%2F5\"\r\n" );
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document.write( "Now use the formula\r\n" );
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document.write( "\"cos%28B%2F2%29\"\"%22%22=%22%22\"\"%22%22+%2B-+sqrt%28%281+%2B+cos%28B%29%29+%2F+2%29\"\r\n" );
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document.write( "We need to determine whether to use the + or the - sign.\r\n" );
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document.write( "Since B is in the 3rd quadrant,  \"pi%3C=B%3C=3pi%2F2\"\r\n" );
document.write( "                                 \"pi%2F2%3C=B%2F2=3pi%2F4\"\r\n" );
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document.write( "Therefore \"B%2F2\" is in quadrant 2, and the cosine will be\r\n" );
document.write( "negative, so\r\n" );
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document.write( "\"cos%28B%2F2%29\"\"%22%22=%22%22\"\"-sqrt%28%281+%2B+cos%28B%29%29+%2F+2%29\"\r\n" );
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document.write( "\"cos%28B%2F2%29\"\"%22%22=%22%22\"\"-sqrt%28%281+%2B+%28-2sqrt%286%29%2F5+%29%29+%2F+2%29\"\r\n" );
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document.write( "Multiply numerator and denominator by 5 to simplify compound fraction:\r\n" );
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document.write( "\"cos%28B%2F2%29\"\"%22%22=%22%22\"\"-sqrt%28++%285+-2sqrt%286%29+%29+%2F+10%29\"\r\n" );
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document.write( "That is the correct answer, but it has a square root within a square\r\n" );
document.write( "root, and often such an expression can be simplified to the sum or\r\n" );
document.write( "difference of two square roots of rational numbers.  Assume rational \r\n" );
document.write( "a and b exist so that\r\n" );
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document.write( "\"-sqrt%28++%285+-2sqrt%286%29+%29+%2F+10%29\"\"%22%22=%22%22\"\"sqrt%28a%29-sqrt%28b%29\"\r\n" );
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document.write( "I will assume a difference since a difference occurs under the square\r\n" );
document.write( "root.\r\n" );
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document.write( "Square both sides\r\n" );
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document.write( "\"++%285+-2sqrt%286%29%29++%2F+10\"\"%22%22=%22%22\"\"a-2sqrt%28ab%29%2Bb\"\r\n" );
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document.write( "Multiply both sides by 10\r\n" );
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document.write( "\"++5+-2sqrt%286%29++\"\"%22%22=%22%22\"\"10a-20sqrt%28ab%29%2B10b\"\r\n" );
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document.write( "We set rational parts equal and irrational parts equal\r\n" );
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document.write( "\"5=10a%2B10b\",  \"2sqrt%286%29=20sqrt%28ab%29\"\r\n" );
document.write( "\"1=2a%2B2b\",     \"sqrt%286%29=10sqrt%28ab%29\"\r\n" );
document.write( "                \"6=100ab\"\r\n" );
document.write( "                \"3=50ab\" \r\n" );
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document.write( "Solve \"3=50ab\" for b, \"b=3%2F%2850a%29\"\r\n" );
document.write( "Substitute in \r\n" );
document.write( "\"1=2a%2B2b\"\r\n" );
document.write( "\"1=2a%2B2%283%2F%2850a%29%29\"\r\n" );
document.write( "\"1=2a%2B3%2F%2825a%29\"\r\n" );
document.write( " Multiply through by 25a\r\n" );
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document.write( "\"25a=50a%5E2%2B3\"\r\n" );
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document.write( "\"0=50a%5E2-25a%2B3\"\r\n" );
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document.write( "\"0=%2810a-3%29%285a-1%29\"\r\n" );
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document.write( "\"a=3%2F10\", \"a=1%2F5\"\r\n" );
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document.write( "Using \"a=3%2F10\", substitute in\r\n" );
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document.write( "\"b=3%2F%2850a%29\"\r\n" );
document.write( "\"b=3%2F%2850%283%2F10%29%29=3%2F%285%2A3%29=1%2F5\"\r\n" );
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document.write( "Using \"a=1%2F5\", substitute in\r\n" );
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document.write( "\"b=3%2F%2850a%29\"\r\n" );
document.write( "\"b=3%2F%2850%281%2F5%29%29=3%2F10\"\r\n" );
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document.write( "So we either have \"a=3%2F10\",\"b=1%2F5\" or \"a=1%2F5\",\"b=3%2F10\"\r\n" );
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document.write( "But since \"cos%28B%2F2%29\" is negative we must choose\r\n" );
document.write( "the second answer:\r\n" );
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document.write( "\"a=1%2F5\",\"b=3%2F10\"\r\n" );
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document.write( "So\r\n" );
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document.write( "\"cos%28B%2F2%29\"\"%22%22=%22%22\"\"-sqrt%28++%285+-2sqrt%286%29+%29+%2F+10%29\"\"%22%22=%22%22\"\"sqrt%28a%29-sqrt%28b%29\"\"%22%22=%22%22\"\"sqrt%281%2F5%29-sqrt%283%2F10%29\"\"%22%22=%22%22\"\"sqrt%285%29%2F5-sqrt%2830%29%2F10\"\r\n" );
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document.write( "Edwin
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