document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=11291>Question 11291</A>: <I><SPAN STYLE=\"word-break: break-all;\"> an oil painting is 16 years older than a water color by the same artist. the oild painting is also three times older than the watercolor. how old is each? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #5869 by </B><A HREF=/tutors/aboutme.mpl?userid=askmemath><B>askmemath(368)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=askmemath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=5869\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the age of the water painting = W<BR>\n" );
document.write( "then Age of oil painting=w+16<BR>\n" );
document.write( "Also water painting =(1/3)oil painting<BR>\n" );
document.write( "W= (1/3)(W+16)<BR>\n" );
document.write( "Multiplying both sides with 3<BR>\n" );
document.write( "3W=W+16<BR>\n" );
document.write( "Subtracting W on both sides<BR>\n" );
document.write( "2W=16<BR>\n" );
document.write( "Dividing both sides with 2<BR>\n" );
document.write( "W=8<BR>\n" );
document.write( "Therefore oil painting = 8+16= 24 </SPAN>\n" );
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