document.write( "Question 960242: 100e^-0.13t=50\r
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document.write( "100=20(1.2)^x+2 \n" );
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Algebra.Com's Answer #586831 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! a.) 100e^-0.13t=50 \n" ); document.write( "e^(-0.13t)=50/100=1/2 \n" ); document.write( "take log of both sides \n" ); document.write( "-0.13t*lne=ln(1/2) \n" ); document.write( "lne=1 \n" ); document.write( "-0.13t=ln(1/2) \n" ); document.write( "t= ln(1/2)/-0.13 \n" ); document.write( "t=-5.3319 \n" ); document.write( ".. \n" ); document.write( "b.) 100=20(1.2)^x+2 \n" ); document.write( "98=20(1.2)^x \n" ); document.write( "1.2^x=98/20=4.9 \n" ); document.write( "xlog1.2=log4.9 \n" ); document.write( "x=log 4.9/log1.2 \n" ); document.write( "x=8.7167 \n" ); document.write( " |