document.write( "Question 960242: 100e^-0.13t=50\r
\n" ); document.write( "\n" ); document.write( "100=20(1.2)^x+2
\n" ); document.write( "

Algebra.Com's Answer #586831 by lwsshak3(11628)\"\" \"About 
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a.) 100e^-0.13t=50
\n" ); document.write( "e^(-0.13t)=50/100=1/2
\n" ); document.write( "take log of both sides
\n" ); document.write( "-0.13t*lne=ln(1/2)
\n" ); document.write( "lne=1
\n" ); document.write( "-0.13t=ln(1/2)
\n" ); document.write( "t= ln(1/2)/-0.13
\n" ); document.write( "t=-5.3319
\n" ); document.write( "..
\n" ); document.write( "b.) 100=20(1.2)^x+2
\n" ); document.write( "98=20(1.2)^x
\n" ); document.write( "1.2^x=98/20=4.9
\n" ); document.write( "xlog1.2=log4.9
\n" ); document.write( "x=log 4.9/log1.2
\n" ); document.write( "x=8.7167
\n" ); document.write( "
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