document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=960161>Question 960161</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When drawing angles in standard position, how do you know to stop because you have reached the correct point?   For example,  if you were drawing the following angle:  -3pi/7, how do you know what degree to stop at?  I can draw the degrees, but the pi's throw me for a loop.  Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #586828 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=586828\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In trig working with degrees, pi is 180 degrees, therefore<BR>\n" );
document.write( "-3pi/7 = (-3*180) / 7 = -540 / 7 = -77.142857143 degrees<BR>\n" );
document.write( "counter clockwise are positive angles and clockwise are negative angles<BR>\n" );
document.write( "the related angle to -77.142857143 is (360 - 77.142857143) = 282.857142857 degrees<BR>\n" );
document.write( "note that the angles 282.857142857 degrees and -77.142857143 degrees are in the fourth quadrant.<BR>\n" );
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