document.write( "Question 960089: If four times a first number is decreased by three times a second number, the result is 0. The sum of the two numbers is -7. \n" ); document.write( "
Algebra.Com's Answer #586780 by ankor@dixie-net.com(22740)\"\" \"About 
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Two numbers, a & b
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\n" ); document.write( " If four times a first number is decreased by three times a second number, the result is 0.
\n" ); document.write( "4a - 3b = 0
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\n" ); document.write( "The sum of the two numbers is -7.
\n" ); document.write( "a + b = -7
\n" ); document.write( "a = -b - 7
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\n" ); document.write( "Replace a with (-b-7) in the first equation
\n" ); document.write( "4(-b-7) - 3b = 0
\n" ); document.write( "-4b - 28 - 3b = 0
\n" ); document.write( "-7b = + 28
\n" ); document.write( "-7b = +28
\n" ); document.write( "b = 28/-7
\n" ); document.write( "b = -4
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\n" ); document.write( "Find a
\n" ); document.write( "a = -(-4) - 7
\n" ); document.write( "a = +4 - 7
\n" ); document.write( "a = -3
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\n" ); document.write( "See if that works in \"If four times a first number is decreased by three times a second number, the result is 0. \"
\n" ); document.write( "4(-3) - 3(-4) =
\n" ); document.write( "-12 + 12 = 0
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