document.write( "Question 960071: How would you graph the equation y=2x+3?\r
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Algebra.Com's Answer #586747 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!

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Solved by pluggable solver: Graphing Linear Equations
In order to graph \"y=2%2Ax%2B3\" we only need to plug in two points to draw the line
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\n" ); document.write( " So lets plug in some points
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\n" ); document.write( " Plug in x=-6
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\n" ); document.write( " \"y=2%2A%28-6%29%2B3\"
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\n" ); document.write( " \"y=-12%2B3\" Multiply
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\n" ); document.write( " \"y=-9\" Add
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\n" ); document.write( " So here's one point (-6,-9)
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\n" ); document.write( " Now lets find another point
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\n" ); document.write( " Plug in x=-5
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\n" ); document.write( " \"y=2%2A%28-5%29%2B3\"
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\n" ); document.write( " \"y=-10%2B3\" Multiply
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\n" ); document.write( " \"y=-7\" Add
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\n" ); document.write( " So here's another point (-5,-7). Add this to our graph
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\n" ); document.write( " Now draw a line through these points
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\n" ); document.write( " So this is the graph of \"y=2%2Ax%2B3\" through the points (-6,-9) and (-5,-7)
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\n" ); document.write( " So from the graph we can see that the slope is \"2%2F1\" (which tells us that in order to go from point to point we have to start at one point and go up 2 units and to the right 1 units to get to the next point) the y-intercept is (0,\"3\")and the x-intercept is (\"-1.5\",0) ,or (\"-3%2F2\",0)
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\n" ); document.write( " We could graph this equation another way. Since \"b=3\" this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,\"3\").
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\n" ); document.write( " So we have one point (0,\"3\")
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\n" ); document.write( " Now since the slope is \"2%2F1\", this means that in order to go from point to point we can use the slope to do so. So starting at (0,\"3\"), we can go up 2 units
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\n" ); document.write( " and to the right 1 units to get to our next point
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\n" ); document.write( " Now draw a line through those points to graph \"y=2%2Ax%2B3\"
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\n" ); document.write( " So this is the graph of \"y=2%2Ax%2B3\" through the points (0,3) and (1,5)
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