document.write( "Question 960000: if the length of a rectangle is four less than twice its width and the area is 48 meters squared find the length and the width \n" ); document.write( "

Algebra.Com's Answer #586712 by macston(5194) $\"\"$ $\"About$

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W=width; L=length=2W-4; A=area=48 sq m
\n" ); document.write( " $\"A=L%2AW\"$ Substitute for L
\n" ); document.write( " $\"A=%282W-4%29%28W%29\"$
\n" ); document.write( " $\"48m%5E2=2W%5E2-4W\"$ Divide each side by 2.
\n" ); document.write( " $\"24m%5E2=W%5E2-2W\"$ Subtract 24 sq m from each side.
\n" ); document.write( " $\"0=W%5E2-2W-24\"$
\n" ); document.write( " $\"0=%28W-6%29%28W%2B4%29\"$
\n" ); document.write( " $\"W-6=0\"$ or $\"W%2B4=0\"$
\n" ); document.write( " $\"W=6\"$ or $\"W=-4\"$ ANSWER 1: The width is 6 meters.
\n" ); document.write( " $\"L=2W-4m\"$ = $\"2%286m%29-4m=12m-4m\"$ = $\"8m\"$ ANSWER 2: The length is 8 meters.
\n" ); document.write( "CHECK:
\n" ); document.write( " $\"A=L%2AW\"$
\n" ); document.write( " $\"48m%5E2=%288m%29%286m%29\"$
\n" ); document.write( " $\"48m%5E2=48m%5E2\"$ \r
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