document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=959814>Question 959814</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the age of a girl and her brother is 26 years.three years age,her age was four times the age of her brother fine their present age..? Plzzzzz help i am having exam  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #586630 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=586630\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be the girls age and y be her brothers age, then<BR>\n" );
document.write( "x + y = 26<BR>\n" );
document.write( "(x-3) = 4(y-3)<BR>\n" );
document.write( "solve fist equation for x and substitute in second equation<BR>\n" );
document.write( "(26-y-3) = 4y -12<BR>\n" );
document.write( "23-y = 4y -12<BR>\n" );
document.write( "add y to both sides of =, then add 12 to both sides of =<BR>\n" );
document.write( "5y = 35<BR>\n" );
document.write( "y = 7 and x = 19<BR>\n" );
document.write( "The girl is 19 and her brother is 7<BR>\n" );
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