document.write( "Question 959328: how do I draw x+y=11 and 2x+3y=26 onto a graph \n" ); document.write( "
Algebra.Com's Answer #586589 by EdenWolf(517)\"\" \"About 
You can put this solution on YOUR website!
1)\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Graphing Linear Equations
In order to graph \"y=-1%2Ax%2B11\" we only need to plug in two points to draw the line
\n" ); document.write( "
\n" ); document.write( " So lets plug in some points
\n" ); document.write( "
\n" ); document.write( " Plug in x=2
\n" ); document.write( "
\n" ); document.write( " \"y=-1%2A%282%29%2B11\"
\n" ); document.write( "
\n" ); document.write( " \"y=-2%2B11\" Multiply
\n" ); document.write( "
\n" ); document.write( " \"y=9\" Add
\n" ); document.write( "
\n" ); document.write( " So here's one point (2,9)
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now lets find another point
\n" ); document.write( "
\n" ); document.write( " Plug in x=3
\n" ); document.write( "
\n" ); document.write( " \"y=-1%2A%283%29%2B11\"
\n" ); document.write( "
\n" ); document.write( " \"y=-3%2B11\" Multiply
\n" ); document.write( "
\n" ); document.write( " \"y=8\" Add
\n" ); document.write( "
\n" ); document.write( " So here's another point (3,8). Add this to our graph
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now draw a line through these points
\n" ); document.write( "
\n" ); document.write( " So this is the graph of \"y=-1%2Ax%2B11\" through the points (2,9) and (3,8)
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So from the graph we can see that the slope is \"-1%2F1\" (which tells us that in order to go from point to point we have to start at one point and go down -1 units and to the right 1 units to get to the next point), the y-intercept is (0,\"11\")and the x-intercept is (\"11\",0)
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " We could graph this equation another way. Since \"b=11\" this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,\"11\").
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So we have one point (0,\"11\")
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now since the slope is \"-1%2F1\", this means that in order to go from point to point we can use the slope to do so. So starting at (0,\"11\"), we can go down 1 units
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " and to the right 1 units to get to our next point
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now draw a line through those points to graph \"y=-1%2Ax%2B11\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So this is the graph of \"y=-1%2Ax%2B11\" through the points (0,11) and (1,10)
\n" ); document.write( "

\n" ); document.write( "\n" ); document.write( "2)\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Graphing Linear Equations

\n" ); document.write( "
\n" ); document.write( " \"2%2Ax%2B3%2Ay=26\"Start with the given equation
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"3%2Ay=26-2%2Ax\" Subtract \"2%2Ax\" from both sides
\n" ); document.write( "
\n" ); document.write( " \"y=%281%2F3%29%2826-2%2Ax%29\" Multiply both sides by \"1%2F3\"
\n" ); document.write( "
\n" ); document.write( " \"y=%281%2F3%29%2826%29-%281%2F3%29%282%29x%29\" Distribute \"1%2F3\"
\n" ); document.write( "
\n" ); document.write( " \"y=26%2F3-%282%2F3%29x\" Multiply
\n" ); document.write( "
\n" ); document.write( " \"y=%28-2%2F3%29%2Ax%2B26%2F3\" Rearrange the terms
\n" ); document.write( "
\n" ); document.write( " \"y=%28-2%2F3%29%2Ax%2B26%2F3\" Reduce any fractions
\n" ); document.write( "
\n" ); document.write( " So the equation is now in slope-intercept form (\"y=mx%2Bb\") where \"m=-2%2F3\" (the slope) and \"b=26%2F3\" (the y-intercept)
\n" ); document.write( "
\n" ); document.write( " So to graph this equation lets plug in some points
\n" ); document.write( "
\n" ); document.write( " Plug in x=1
\n" ); document.write( "
\n" ); document.write( " \"y=%28-2%2F3%29%2A%281%29%2B26%2F3\"
\n" ); document.write( "
\n" ); document.write( " \"y=-2%2F3%2B26%2F3\" Multiply
\n" ); document.write( "
\n" ); document.write( " \"y=24%2F3\" Add
\n" ); document.write( "
\n" ); document.write( " \"y=8\" Reduce
\n" ); document.write( "
\n" ); document.write( " So here's one point (1,8)
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now lets find another point
\n" ); document.write( "
\n" ); document.write( " Plug in x=4
\n" ); document.write( "
\n" ); document.write( " \"y=%28-2%2F3%29%2A%284%29%2B26%2F3\"
\n" ); document.write( "
\n" ); document.write( " \"y=-8%2F3%2B26%2F3\" Multiply
\n" ); document.write( "
\n" ); document.write( " \"y=18%2F3\" Add
\n" ); document.write( "
\n" ); document.write( " \"y=6\" Reduce
\n" ); document.write( "
\n" ); document.write( " So here's another point (4,6). Add this to our graph
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now draw a line through these points
\n" ); document.write( "
\n" ); document.write( " So this is the graph of \"y=%28-2%2F3%29%2Ax%2B26%2F3\" through the points (1,8) and (4,6)
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So from the graph we can see that the slope is \"-2%2F3\" (which tells us that in order to go from point to point we have to start at one point and go down -2 units and to the right 3 units to get to the next point), the y-intercept is (0,\"8.66666666666667\") ,or (0,\"26%2F3\"), and the x-intercept is (\"13\",0) . So all of this information verifies our graph.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " We could graph this equation another way. Since \"b=26%2F3\" this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,\"26%2F3\").
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So we have one point (0,\"26%2F3\")
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now since the slope is \"-2%2F3\", this means that in order to go from point to point we can use the slope to do so. So starting at (0,\"26%2F3\"), we can go down 2 units
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " and to the right 3 units to get to our next point
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Now draw a line through those points to graph \"y=%28-2%2F3%29%2Ax%2B26%2F3\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So this is the graph of \"y=%28-2%2F3%29%2Ax%2B26%2F3\" through the points (0,8.66666666666667) and (3,6.66666666666667)
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" );