document.write( "Question 959586: The amount A paid to a work crew varies jointly as the number of persons working N and the length of time worked t. If 5 bricklayers take 6 days to finish a certain job, how long would it take 7 bricklayers to finish a similar job requiring 4 times the number of bricks?\r
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Algebra.Com's Answer #586527 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
You can say:
\n" ); document.write( "5 bricklayers take 6 days to do 1 job
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\n" ); document.write( "If another job requires 4 times the number of bricks
\n" ); document.write( "you can say that is 4 jobs, so
\n" ); document.write( "7 bricklayers take \"+d+\" days to finish 4 jobs
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\n" ); document.write( "7 times as many bricklayers can do 1 job in 1/7 the time, so
\n" ); document.write( "35 bricklayers take 6/7 days to do 1 job
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\n" ); document.write( "1/5 as many bricklayers will take 5 times as long, so
\n" ); document.write( "7 bricklayers take 30/7 days to do 1 job
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\n" ); document.write( "4 jobs will take 4 times as long, so
\n" ); document.write( "7 bricklayers take 120/7 days to do 4 jobs
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\n" ); document.write( "\"+120%2F7+=+17+%2B+1%2F7+\", so
\n" ); document.write( "7 bricklayers take 17 and 1/7 days to do 4 jobs
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\n" ); document.write( "Hope I got it\r
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